DateValue
Returns a Date Serial from a string
#include "vbcompat.bi"
result = DateValue( date_string )
date_string
The date string must be in the format set in the regional settings of the Operating System.
DateValue( Date() ) will work correctly only if the regional settings specify the same short date format QB used (mm-dd-yyyy). Consider using the Now function in the expression Fix(Now()) to obtain the current date as a date serial.
The compiler will not recognize this function unless vbcompat.bi or datetime.bi is included.
Syntax
Usage
#include "vbcompat.bi"
result = DateValue( date_string )
Parameters
date_string
the string to convert to a date serial
Return Value
Description
The date string must be in the format set in the regional settings of the Operating System.
DateValue( Date() ) will work correctly only if the regional settings specify the same short date format QB used (mm-dd-yyyy). Consider using the Now function in the expression Fix(Now()) to obtain the current date as a date serial.
The compiler will not recognize this function unless vbcompat.bi or datetime.bi is included.
Example
#include "vbcompat.bi"
Dim As Integer v1, v2
Dim As String s1, s2
Print "Enter first date: ";
Line Input s1
If IsDate( s1 ) = 0 Then
Print "not a date"
End
End If
Print "Enter second date: ";
Line Input s2
If IsDate( s2 ) = 0 Then
Print "not a date"
End
End If
'' convert the strings to date serials
v1 = DateValue( s1 )
v2 = DateValue( s2 )
Print "Number of days between dates is " & Abs( v2 - v1 )
Dim As Integer v1, v2
Dim As String s1, s2
Print "Enter first date: ";
Line Input s1
If IsDate( s1 ) = 0 Then
Print "not a date"
End
End If
Print "Enter second date: ";
Line Input s2
If IsDate( s2 ) = 0 Then
Print "not a date"
End
End If
'' convert the strings to date serials
v1 = DateValue( s1 )
v2 = DateValue( s2 )
Print "Number of days between dates is " & Abs( v2 - v1 )
Differences from QB
- Did not exist in QB. This function appeared in PDS and VBDOS
See also