| Mouse.ButtonWait | Part of Mouse module |
| Syntax | Mouse.ButtonWait (motion : string,
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| Description | The Mouse.ButtonWait procedure gets information about a mouse event and removes it from the queue. The parameter motion must be one of "up", "down", "updown" or "downup". If an event of the type requested is in the queue, Mouse.ButtonWait returns instantly. If there isn't such an event, Mouse.ButtonWait waits until there is one and then returns (much like getch handles keystrokes). In "single-button mode" (where the mouse is treated like a one-button mouse), a "down" event occurs whenever all the buttons are up and a button is pressed. An "up" event takes place when the last button is released so that no buttons remain pressed. In "multi-button mode", a "down" event occurs whenever any button is pressed, and an "up" event occurs whenever any button is released. The parameters x and y are set to the position of the mouse cursor when the button was pressed. The parameter buttonnumber is set to 1 when in "single-button mode". In "multi-button mode", it is set to 1 if the left button was pressed, 2 if the middle button was pressed, and 3 if the right button was pressed. The parameter buttonupdown is set to 1, if a button was pressed and 0 if a button was released.
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| Example | This program draws lines. It starts a line where the user presses down and continues to update the line while the mouse button is held down. When the button is released, the line is permanently draw and the user can draw another line.
var x, y, btnNumber, btnUpDown, buttons : int
var nx, ny : int
loop
Mouse.ButtonWait ("down", x, y, btnNumber, btnUpDown)
nx := x
ny := y
loop
Draw.Line (x, y, nx, ny, 0) % Erase previous line
exit when Mouse.ButtonMoved ("up")
Mouse.Where (nx, ny, buttons)
Draw.Line (x, y, nx, ny, 1) % Draw line to position
end loop
Mouse.ButtonWait ("up", nx, ny, btnNumber, btnUpDown)
Draw.Line (x, y, nx, ny, 2) % Draw line to final position
end loop
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| Example | This is an example demonstrating how to check for both character and mouse input at the same time.
var ch : string (1)
var x, y, btnNum, btnUpDown : int
loop
if hasch then
getch (ch)
Text.Locate (1, 1)
put "The character entered is a: ", ch
end if
if Mouse.ButtonMoved ("down") then
Mouse.ButtonWait ("down", x, y, btnNum, btnUpDown)
Text.Locate (1, 1)
put "The button was clicked at position: ", x, ", ",y
end if
end loop
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| Details | Mouse.ButtonWait can be thought of as the mouse equivalent of getch in that they both read something in a queue and both wait until they get the thing they're looking for.
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| Status | Exported qualified. This means that you can only call the function by calling Mouse.ButtonWait, not by calling ButtonWait.
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| See also | Mouse.ButtonWait to see if an appropriate event is in the queue. See also Mouse.ButtonChoose to switch between "single-button mode" and "multi-button mode".
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