LIN Bus Timing

As LIN is a polled bus, processing of each frame is allocated a nominal time slot as follows:

T_{Header_Nominal} = 34 * T_Bit

T_{Response_Nominal} = 10 * (N_Data + 1) * T_Bit

T_{Frame_Nominal} = T_{Header_Nominal} + T_{Response_Nominal}

Processing of each frame is allocated a maximum time slot as follows:

T_{Header_Maximum} = 14 * T_{Header_Nominal}

T_{Response_Maximum} = 1.4 * T_{Response_Nominal}

T_{Frame_Maximum} = T_{Header_Maximum} + T_{Response_Maximum}