jQuery.inArray()

jQuery

jQuery.inArray()


jQuery.inArray( value, array [, fromIndex ] ) Returns: Number

Description: Search for a specified value within an array and return its index (or -1 if not found).

  • version added: 1.2jQuery.inArray( value, array [, fromIndex ] )

    • value
      Type: Anything
      The value to search for.
    • array
      Type: Array
      An array through which to search.
    • fromIndex
      Type: Number
      The index of the array at which to begin the search. The default is 0, which will search the whole array.

The $.inArray() method is similar to JavaScript's native .indexOf() method in that it returns -1 when it doesn't find a match. If the first element within the array matches value, $.inArray() returns 0.

Because JavaScript treats 0 as loosely equal to false (i.e. 0 == false, but 0 !== false), if we're checking for the presence of value within array, we need to check if it's not equal to (or greater than) -1.

Example:

Report the index of some elements in the array.

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<!DOCTYPE html>
<html>
<head>
<style>
div { color:blue; }
span { color:red; }
</style>
<script src="http://code.jquery.com/jquery-latest.js"></script>
</head>
<body>
<div>"John" found at <span></span></div>
<div>4 found at <span></span></div>
<div>"Karl" not found, so <span></span></div>
<div>"Pete" is in the array, but not at or after index 2, so <span></span></div>
<script> var arr = [ 4, "Pete", 8, "John" ];
var $spans = $("span");
$spans.eq(0).text(jQuery.inArray("John", arr));
$spans.eq(1).text(jQuery.inArray(4, arr));
$spans.eq(2).text(jQuery.inArray("Karl", arr));
$spans.eq(3).text(jQuery.inArray("Pete", arr, 2));
</script>
</body>
</html>