PointAndDerivatives method
Returns a point and derivatives at a position along a curve's path.
Version added
5.0
Syntax
| |
object |
Required. An expression that returns a Curve object. |
t |
Required Double. The value in the curve's parameter domain to evaluate. |
n |
Required Integer. 0: get point; 1: point and 1st derivative; 2: point plus first and second derivative. |
x |
Required Double. Returns x value of curve at t. |
y |
Required Double. Returns y value of curve at t. |
dx |
Required Double. Returns first derivative (dx/dt) at t if n > 0. |
dy |
Required Double. Returns first derivative (dx/dt) at t if n > 0. |
ddx |
Required Double. Returns second derivative (ddx/dt) at t if n > 1. |
ddy |
Required Double. Returns second derivative (ddy/dt) at t if n > 1. |
Remarks
Use the PointAndDerivatives method of the Curve object to obtain the coordinates of a point within the curve's parameter domain and its first and second derivatives.
A Curve object describes itself in terms of its parameter domain which is the range [Start(),End()]. The PointAndDerivatives method can be used to extrapolate the curve's path outside [Start(),End()].