7.3.4 Tuple Objects
- This subtype of PyObject represents a Python tuple object.
-
This instance of PyTypeObject represents the Python tuple
type; it is the same object as
types.TupleType
in the Python layer..
- Return true if p is a tuple object or an instance of a subtype of the tuple type. Changed in version 2.2: Allowed subtypes to be accepted.
- Return true if p is a tuple object, but not an instance of a subtype of the tuple type. New in version 2.2.
-
Return value: New reference.Return a new tuple object of size len, or NULL on failure.
- Return a new tuple object of size n, or NULL on failure. The tuple values are initialized to the subsequent n C arguments pointing to Python objects. "PyTuple_Pack(2, a, b)" is equivalent to "Py_BuildValue("(OO)", a, b)". New in version 2.4.
- Takes a pointer to a tuple object, and returns the size of that tuple.
- Return the size of the tuple p, which must be non-NULL and point to a tuple; no error checking is performed.
-
Return value: Borrowed reference.Returns the object at position pos in the tuple pointed to by p. If pos is out of bounds, returns NULL and sets an IndexError exception.
-
Return value: Borrowed reference.Like PyTuple_GetItem(), but does no checking of its arguments.
-
Return value: New reference.Takes a slice of the tuple pointed to by p from low to high and returns it as a new tuple.
-
Inserts a reference to object o at position pos of the
tuple pointed to by p. It returns
0
on success. Note: This function ``steals'' a reference to o.
- Like PyTuple_SetItem(), but does no error checking, and should only be used to fill in brand new tuples. Note: This function ``steals'' a reference to o.
-
Can be used to resize a tuple. newsize will be the new length
of the tuple. Because tuples are supposed to be immutable,
this should only be used if there is only one reference to the
object. Do not use this if the tuple may already be known to
some other part of the code. The tuple will always grow or shrink
at the end. Think of this as destroying the old tuple and creating
a new one, only more efficiently. Returns
0
on success. Client code should never assume that the resulting value of*p
will be the same as before calling this function. If the object referenced by*p
is replaced, the original*p
is destroyed. On failure, returns-1
and sets*p
to NULL, and raises MemoryError or SystemError. Changed in version 2.2: Removed unused third parameter, last_is_sticky.
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