Source file src/pkg/math/sqrt.go
1 // Copyright 2009 The Go Authors. All rights reserved. 2 // Use of this source code is governed by a BSD-style 3 // license that can be found in the LICENSE file. 4 5 package math 6 7 // Sqrt returns the square root of x. 8 // 9 // Special cases are: 10 // Sqrt(+Inf) = +Inf 11 // Sqrt(±0) = ±0 12 // Sqrt(x < 0) = NaN 13 // Sqrt(NaN) = NaN 14 func Sqrt(x float64) float64 15 16 // The original C code and the long comment below are 17 // from FreeBSD's /usr/src/lib/msun/src/e_sqrt.c and 18 // came with this notice. The go code is a simplified 19 // version of the original C. 20 // 21 // ==================================================== 22 // Copyright (C) 1993 by Sun Microsystems, Inc. All rights reserved. 23 // 24 // Developed at SunPro, a Sun Microsystems, Inc. business. 25 // Permission to use, copy, modify, and distribute this 26 // software is freely granted, provided that this notice 27 // is preserved. 28 // ==================================================== 29 // 30 // __ieee754_sqrt(x) 31 // Return correctly rounded sqrt. 32 // ----------------------------------------- 33 // | Use the hardware sqrt if you have one | 34 // ----------------------------------------- 35 // Method: 36 // Bit by bit method using integer arithmetic. (Slow, but portable) 37 // 1. Normalization 38 // Scale x to y in [1,4) with even powers of 2: 39 // find an integer k such that 1 <= (y=x*2**(2k)) < 4, then 40 // sqrt(x) = 2**k * sqrt(y) 41 // 2. Bit by bit computation 42 // Let q = sqrt(y) truncated to i bit after binary point (q = 1), 43 // i 0 44 // i+1 2 45 // s = 2*q , and y = 2 * ( y - q ). (1) 46 // i i i i 47 // 48 // To compute q from q , one checks whether 49 // i+1 i 50 // 51 // -(i+1) 2 52 // (q + 2 ) <= y. (2) 53 // i 54 // -(i+1) 55 // If (2) is false, then q = q ; otherwise q = q + 2 . 56 // i+1 i i+1 i 57 // 58 // With some algebraic manipulation, it is not difficult to see 59 // that (2) is equivalent to 60 // -(i+1) 61 // s + 2 <= y (3) 62 // i i 63 // 64 // The advantage of (3) is that s and y can be computed by 65 // i i 66 // the following recurrence formula: 67 // if (3) is false 68 // 69 // s = s , y = y ; (4) 70 // i+1 i i+1 i 71 // 72 // otherwise, 73 // -i -(i+1) 74 // s = s + 2 , y = y - s - 2 (5) 75 // i+1 i i+1 i i 76 // 77 // One may easily use induction to prove (4) and (5). 78 // Note. Since the left hand side of (3) contain only i+2 bits, 79 // it does not necessary to do a full (53-bit) comparison 80 // in (3). 81 // 3. Final rounding 82 // After generating the 53 bits result, we compute one more bit. 83 // Together with the remainder, we can decide whether the 84 // result is exact, bigger than 1/2ulp, or less than 1/2ulp 85 // (it will never equal to 1/2ulp). 86 // The rounding mode can be detected by checking whether 87 // huge + tiny is equal to huge, and whether huge - tiny is 88 // equal to huge for some floating point number "huge" and "tiny". 89 // 90 // 91 // Notes: Rounding mode detection omitted. The constants "mask", "shift", 92 // and "bias" are found in src/pkg/math/bits.go 93 94 // Sqrt returns the square root of x. 95 // 96 // Special cases are: 97 // Sqrt(+Inf) = +Inf 98 // Sqrt(±0) = ±0 99 // Sqrt(x < 0) = NaN 100 // Sqrt(NaN) = NaN 101 func sqrt(x float64) float64 { 102 // special cases 103 switch { 104 case x == 0 || IsNaN(x) || IsInf(x, 1): 105 return x 106 case x < 0: 107 return NaN() 108 } 109 ix := Float64bits(x) 110 // normalize x 111 exp := int((ix >> shift) & mask) 112 if exp == 0 { // subnormal x 113 for ix&1<<shift == 0 { 114 ix <<= 1 115 exp-- 116 } 117 exp++ 118 } 119 exp -= bias // unbias exponent 120 ix &^= mask << shift 121 ix |= 1 << shift 122 if exp&1 == 1 { // odd exp, double x to make it even 123 ix <<= 1 124 } 125 exp >>= 1 // exp = exp/2, exponent of square root 126 // generate sqrt(x) bit by bit 127 ix <<= 1 128 var q, s uint64 // q = sqrt(x) 129 r := uint64(1 << (shift + 1)) // r = moving bit from MSB to LSB 130 for r != 0 { 131 t := s + r 132 if t <= ix { 133 s = t + r 134 ix -= t 135 q += r 136 } 137 ix <<= 1 138 r >>= 1 139 } 140 // final rounding 141 if ix != 0 { // remainder, result not exact 142 q += q & 1 // round according to extra bit 143 } 144 ix = q>>1 + uint64(exp-1+bias)<<shift // significand + biased exponent 145 return Float64frombits(ix) 146 } 147 148 func sqrtC(f float64, r *float64) { 149 *r = sqrt(f) 150 }