







[This topic is pre-release documentation and is subject to change in future releases. Blank topics are included as placeholders.]
Overload List
Name | Description | |
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![]() ![]() | LexicographicalCompare<(Of <T>)>(IEnumerable<(Of <T>)>, IEnumerable<(Of <T>)>) |
Performs a lexicographical comparison of two sequences of values. A lexicographical comparison compares corresponding
pairs of elements from two sequences in order. If the first element of sequence1 is less than the first element of sequence2,
then the comparison ends and the first sequence is lexicographically less than the second. If the first elements of each sequence
are equal, then the comparison proceeds to the second element of each sequence. If one sequence is shorter than the other,
but corresponding elements are all equal, then the shorter sequence is considered less than the longer one.
|
![]() ![]() | LexicographicalCompare<(Of <T>)>(IEnumerable<(Of <T>)>, IEnumerable<(Of <T>)>, IComparer<(Of <T>)>) |
Performs a lexicographical comparison of two sequences of values, using a supplied comparer interface. A lexicographical comparison compares corresponding
pairs of elements from two sequences in order. If the first element of sequence1 is less than the first element of sequence2,
then the comparison ends and the first sequence is lexicographically less than the second. If the first elements of each sequence
are equal, then the comparison proceeds to the second element of each sequence. If one sequence is shorter than the other,
but corresponding elements are all equal, then the shorter sequence is considered less than the longer one.
|
![]() ![]() | LexicographicalCompare<(Of <T>)>(IEnumerable<(Of <T>)>, IEnumerable<(Of <T>)>, Comparison<(Of <T>)>) |
Performs a lexicographical comparison of two sequences of values, using a supplied comparison delegate. A lexicographical comparison compares corresponding
pairs of elements from two sequences in order. If the first element of sequence1 is less than the first element of sequence2,
then the comparison ends and the first sequence is lexicographically less than the second. If the first elements of each sequence
are equal, then the comparison proceeds to the second element of each sequence. If one sequence is shorter than the other,
but corresponding elements are all equal, then the shorter sequence is considered less than the longer one.
|