现在来考虑Customer
,Order
, LineItem
和 Product
关系的模型。Customer
和 Order
之间
是一对多的关系,但是我们怎么来描述Order
/ LineItem
/ Product
呢?
我可以把LineItem
作为描述Order
和 Product
多对多关系的关联类,在Hibernate,这叫做组合元素。
映射文件如下:
<hibernate-mapping> <class name="Customer" table="customers"> <id name="id"> <generator class="native"/> </id> <property name="name"/> <set name="orders" inverse="true"> <key column="customer_id"/> <one-to-many class="Order"/> </set> </class> <class name="Order" table="orders"> <id name="id"> <generator class="native"/> </id> <property name="date"/> <many-to-one name="customer" column="customer_id"/> <list name="lineItems" table="line_items"> <key column="order_id"/> <list-index column="line_number"/> <composite-element class="LineItem"> <property name="quantity"/> <many-to-one name="product" column="product_id"/> </composite-element> </list> </class> <class name="Product" table="products"> <id name="id"> <generator class="native"/> </id> <property name="serialNumber"/> </class> </hibernate-mapping>
customers
, orders
, line_items
和
products
分别保存着customer, order, order line item 和 product的数据。
line_items
也作为连接orders 和 products的关联表。
create table customers ( id BIGINT not null generated by default as identity, name VARCHAR(255), primary key (id) ) create table orders ( id BIGINT not null generated by default as identity, customer_id BIGINT, date TIMESTAMP, primary key (id) ) create table line_items ( line_number INTEGER not null, order_id BIGINT not null, product_id BIGINT, quantity INTEGER, primary key (order_id, line_number) ) create table products ( id BIGINT not null generated by default as identity, serialNumber VARCHAR(255), primary key (id) ) alter table orders add constraint ordersFK0 foreign key (customer_id) references customers alter table line_items add constraint line_itemsFK0 foreign key (product_id) references products alter table line_items add constraint line_itemsFK1 foreign key (order_id) references orders